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The Sun provides warmth and light that is essential for life on Earth. But have you ever wondered what powers this immense ball of fire? The answer lies in nuclear fusion, a process that occurs deep within the core of the Sun and other stars, where lighter atomic nuclei combine to form heavier nuclei, releasing vast amounts of energy in the process. In this lesson, we’ll explore how nuclear fusion works, the different types of fusion reactions in stars, and how these reactions shape the life cycles of stars and contribute to the formation of elements in the universe.

Video

Watch this video for an excellent overview of nuclear fusion and its role in powering stars.


What is Nuclear Fusion?

Nuclear fusion is the process by which two light atomic nuclei combine to form a heavier nucleus, releasing energy in the process. This reaction is the primary energy source for stars, including our Sun.

Conditions for Fusion: For nuclear fusion to occur, the nuclei must overcome their natural repulsion due to their positive charges. This requires extremely high temperatures (millions of degrees) and pressures, which are found in the cores of stars. The immense gravitational force in a star’s core compresses the gas to such an extent that the temperature rises high enough to allow fusion to occur.

Did You Know? The Sun’s core temperature is around 15 million degrees Celsius, a condition necessary for hydrogen nuclei to fuse into helium.


The Proton-Proton Chain Reaction

The proton-proton (p-p) chain is the dominant fusion process in stars the size of the Sun. It involves a series of reactions where hydrogen nuclei (protons) combine to form helium, releasing energy at each step.

Step-by-Step Process:

  1. Step 1: Formation of Deuterium
    • Two protons collide at high speeds. Normally, they would repel each other due to their positive charges, but under the extreme conditions in a star’s core, one proton undergoes beta decay and converts into a neutron. This forms Deuterium (Hydrogen-2), consisting of one proton and one neutron.
    • Reaction: The first step involves the fusion of two protons ($^1\text{H}$) to form deuterium ($^2\text{H}$), releasing a positron ($e^+$) and a neutrino ($\nu_e$).
      \[^1\text{H} + ^1\text{H} \rightarrow ^2\text{H} + e^+ + \nu_e\]

Here, the superscripts indicate the total number of protons and neutrons in the nucleus.

  • Time Scale: This step is the slowest, taking about a billion years on average for a proton in the Sun.

PP Chain Step 1

  1. Step 2: Formation of Helium-3
    • The newly formed Deuterium nucleus collides with another proton, resulting in the formation of Helium-3 (two protons and one neutron).
    • Reaction: In the second step, the deuterium nucleus ($^2\text{H}$) produced in the first step fuses with another proton to form helium-3 ($^3\text{He}$), releasing a gamma-ray photon.
      \[^2\text{H} + ^1\text{H} \rightarrow ^3\text{He} + \gamma\]
    • Time Scale: This reaction happens quickly, in about 4 seconds.

PP Chain Step 2

  1. Step 3: Formation of Helium-4
    • Finally, two Helium-3 nuclei collide to form Helium-4 (two protons and two neutrons) and release two protons.
    • Reaction: The third step involves the fusion of two helium-3 nuclei ($^3\text{He}$) to form helium-4 ($^4\text{He}$) and two protons.
      \[^3\text{He} + ^3\text{He} \rightarrow ^4\text{He} + ^1\text{H} + ^1\text{H}\]
    • Time Scale: This step takes about 400 years for Helium-3 nuclei to collide in the Sun’s core.

Note:

The third step requires two helium-3 nuclei to start; the first two steps must happen twice before the third step can occur.

PP Chain Step 3

Timing:

Although the first step in this chain of reactions is very unlikely to occur at any given moment and typically takes a very long time for a single proton to undergo fusion, the sheer number of protons in the Sun ensures that these reactions are happening constantly. Even though each individual reaction might take billions of years to occur, with countless protons in the Sun’s core, millions of these reactions are happening every second. Despite the slow probability for any single proton, the continuous, overlapping activity of countless atoms makes fusion a steady and powerful energy source.

Proton-Proton Chain Summary:

The proton-proton chain converts four hydrogen nuclei into one helium nucleus, releasing energy in the form of light and heat. This energy is what powers the Sun and provides the warmth and light we receive on Earth.

Energy Generation in the Proton-Proton (p-p) Chain

In the proton-proton (p-p) chain, four hydrogen nuclei (protons) are ultimately fused to form a single helium-4 nucleus. The overall reaction can be represented as:

\[^1\text{H} + ^1\text{H} + ^1\text{H} + ^1\text{H} \rightarrow ^4\text{He} + 2e^+ + 2\nu_e + 2\gamma + \text{energy}\]

To determine the amount of energy released during this process, we can calculate the difference in mass between the initial hydrogen atoms and the final helium atom. The mass of a hydrogen atom is 1.007825 atomic mass units (u), and the mass of a helium-4 atom is 4.00268 u. Here, we use the full atomic mass, including electrons, because the process involves the creation and annihilation of positrons and electrons.

The mass of the initial four hydrogen atoms is:

\[4 \times 1.007825 \, \text{u} = 4.03130 \, \text{u}\]

The mass of the final helium atom is:

\[4.00268 \, \text{u}\]

The difference in mass, which is converted to energy, is:

\[4.03130 \, \text{u} - 4.00268 \, \text{u} = 0.02862 \, \text{u}\]

p-p Chain Mass loss:

The mass loss of one proton-proton (p-p) chain reaction is 0.02862 u, which represents about 0.71% of the initial mass. Therefore, when 1 kilogram of hydrogen is converted into helium, approximately 0.0071 kilograms of mass is converted into energy.

Using Einstein’s mass-energy equivalence formula, $E = mc^2$, where $c$ is the speed of light ($3 \times 10^8$ meters per second), the energy released by this mass conversion is:

\[E = 0.0071 \, \text{kg} \times \left(3 \times 10^8 \, \text{m/s}\right)^2 = 6.4 \times 10^{14} \, \text{J}\]

This amount of energy, released from the fusion of just 1 kilogram of hydrogen, is enough to supply all the electricity used in the United States for approximately two weeks.

The Sun, which shines with a luminosity of $4 \times 10^{26}$ watts, must fuse about 600 million tons of hydrogen into helium every second to maintain its brightness. Of this, around 4 million tons of mass are converted directly into energy. Despite the enormous quantities involved, the Sun has such a vast reserve of hydrogen that it can continue this fusion process for billions of years, ensuring its place as our solar system’s energy source for a long time to come.


The CNO Cycle

In stars more massive than the Sun, the Carbon-Nitrogen-Oxygen (CNO) cycle dominates as the primary fusion process. While it still converts hydrogen into helium, it uses carbon, nitrogen, and oxygen as catalysts.

Overview:

Comparison with Proton-Proton Chain:

Did You Know?

In stars with more than 1.3 times the mass of the Sun, the CNO cycle is the primary energy source.

Energy Transport in Stars

The energy produced by nuclear fusion in the core of a star must journey to the star’s surface before it can be radiated into space as light and heat. This energy travels through various layers of the star, each with unique properties that influence how energy is transferred.

Radiative Zone:

Convection Zone:

Star Layers

Interesting Side Note

Despite the fact that light travels at an incredible speed—about 300,000 kilometers per second in a vacuum—the energy produced in the Sun's core can take thousands of years to reach the surface. This is because photons are continuously absorbed and re-emitted in the radiative zone, making their journey to the surface a slow and winding path. By the time a photon reaches the surface, its journey might have taken several million years!

Photon Path


Nuclear Fusion and Star Life Cycles

Nuclear fusion is not only the engine that powers stars; it also shapes their entire life cycle, from their stable years on the main sequence to their dramatic ends.

The Role of Fusion in Stellar Evolution:

Hydrostatic equilibrium

Helium Burning and Beyond:


Check Your Understanding

  1. Proton-Proton Chain: Describe the steps involved in the proton-proton chain reaction in stars like the Sun. Why is the first step the slowest?

  2. Energy Transport: Explain how energy is transported from the core of the Sun to its surface. Why does this process take so long?

  3. Stellar Nucleosynthesis: How does nucleosynthesis in stars contribute to the formation of elements in the universe? Why are supernovae important for element distribution?

  4. Energy Released in Fusion: Calculate the energy released when a proton combines with a deuterium nucleus to form helium-3 ($^3\text{He}$). Use the following atomic masses: $^1\text{H} = 1.007825 \, \text{u}$, $^2\text{H} = 2.014102 \, \text{u}$, and $^3\text{He} = 3.016029 \, \text{u}$. Apply Einstein’s equation $E = mc^2$, where $c = 3 \times 10^8 \, \text{m/s}$, and note that 1 u = $1.66054 \times 10^{-27}$ kg.

  5. Energy Conversion Over Time: The Sun converts $4 \times 10^9$ kg of mass to energy every second. How many years would it take the Sun to convert a mass equal to the mass of Earth ($6 \times 10^{24}$ kg) to energy?

  6. Total Energy Potential of the Sun: Assume that the Sun’s mass is 75% hydrogen and that all of this mass could be converted to energy according to Einstein’s equation $E = mc^2$. The mass of the Sun is $2 \times 10^{30}$ kg. How much total energy could the Sun generate? Express your answer in joules.

  7. Total Energy from Solar Hydrogen: If all the hydrogen atoms in the Sun were converted into helium, how much total energy would be produced? Estimate the total number of hydrogen atoms in the Sun, considering that hydrogen constitutes 75% of the Sun’s mass. (Hint: The mass of one hydrogen atom is approximately $1.67 \times 10^{-27}$ kg.)

  8. Sun’s Mass Reduction Over Time: The Sun converts 4 million tons of matter into energy every second. How long will it take for the Sun to reduce its mass by 1%? Compare your result with the Sun’s current age of approximately 4.6 billion years. The mass of the Sun is $2 \times 10^{30}$ kg.


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